264=2w^2+2w

Solution for 264=2w^2+2w equation:

264=2w^2+2w

We move all terms to the left:

264-(2w^2+2w)=0

We get rid of parentheses

-2w^2-2w+264=0

a = -2; b = -2; c = +264;
Δ = b2-4ac
Δ = -22-4·(-2)·264
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-46}{2*-2}=\frac{-44}{-4}
=+11
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+46}{2*-2}=\frac{48}{-4}
=-12
$